LINQ SkipLast

Summary: in this tutorial, you will learn how to use the LINQ SkipLast() method to bypass a specified number of elements from the end of a sequence.

Introduction to the LINQ SkipLast() method

The LINQ SkipLast() method allows you to skip the last count elements from a sequence and return the remaining elements after skipping.

Here’s the syntax for using the SkipLast() method:

IEnumerable<T> SkipLast<TSource>(
    this IEnumerable<TSource> source,
    int count
)Code language: C# (cs)

In this syntax:

• source is the input sequence of elements.
• count is the number of elements to skip.

The SkipLast() method returns an IEnumerable<TSource> of the elements after skipping the last count elements.

LINQ SkipLast() method example

The following example uses the LINQ SkipLast() to skip the last three numbers in a list of integers:

using static System.Console;

var numbers = new List<int> { 1, 2, 3, 4, 5, 6, 7 };

var result = numbers.SkipLast(3);
foreach (var number in result)
{
    WriteLine(number);
}Code language: C# (cs)

Output:

1
2
3
4Code language: C# (cs)

Summary

• Use the LINQ SkipLast() method to bypass a specified number of elements from the end of a sequence and return the remaining elements after skipping.